Question 661: Thermodynamics & KTG

Question

The volume of given mass of a gas is increased by $7 \%$ at constant temperature. The pressure should be increased by

Accepted Answer

According to Boyle's Law, $\mathrm{PV}=$ constant
$$ P_1 V_1=P_2 V_2 $$
$\mathrm{V}_2=1.07 \mathrm{~V}_1\,\,\,\,\,\ldots .\left(\because \mathrm{V}_2ight.$ is $7 \%$ more than $\left.\mathrm{V}_1ight)$
$$ \begin{aligned} & P_1 V_1=P_2 	imes\left(1.07 V_1ight) \ 	herefore & P_1=\frac{P_2 	imes 1.07 V_1}{V_1} \ & P_2=\frac{P_1}{1.07}=0.934 P_1 \ 	herefore & \% 	ext { Increase in pressure } \ & =\frac{	ext { final pressure - initial pressure }}{	ext { initial pressure }} 	imes 100 \ & =\frac{0.934 P_1-P_1}{P_1} 	imes 100 \ & =0.065 	imes 100=6.5 \% \end{aligned} $$

Answer

$7 \%$

Answer

$14 \%$

Answer

$7.52 \%$

Answer

$14.52 \%$

Thermodynamics & KTG

The volume of given mass of a gas is increased by 7 \% at constant temperature. The pressure should be increased by

Choose the correct answer: