Question 844: Thermodynamics & KTG

Question

Let $$\gamma_1$$ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and $$\gamma_2$$ be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio $$\frac{\gamma_2}{\gamma_1}$$ is

Accepted Answer

For monoatomic gas,
$$\gamma_1=\frac{5}{3}$$
For rigid diatomic gas,
$$\begin{aligned}
\gamma_2 & =\frac{7}{5} \
	herefore \quad \frac{\gamma_2}{\gamma_1} & =\frac{7}{5} 	imes \frac{3}{5}=\frac{21}{25}
\end{aligned}$$

Answer

$$\frac{37}{21}$$

Answer

$$\frac{27}{35}$$

Answer

$$\frac{21}{25}$$

Answer

$$\frac{35}{27}$$

Thermodynamics & KTG

Let $\gamma_1 be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and \gamma_2 be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio \frac{\gamma_2}{\gamma_1}$ is

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