Question 92: Thermodynamics & KTG

Question

One mole of a monatomic ideal gas undergoes a cyclic process as shown in the figure (where $$V$$ is the volume and $$T$$ is the temperature). Which of the statements below is (are) true?

Accepted Answer

In process I, volume is changing. Therefore, it is not isochoric. Therefore 'A' is incorrect.
In process II, q = $$\Delta$$U + W . $$\Delta$$U = 0 as temperature is constant. Therefore, q = W. Here W = P(V
f
$$-$$ V
i
) is positive therefore q is positive i.e., gas absorbs heat. Therefore 'B' is correct.
For process IV, q = $$\Delta$$U + W. Here $$\Delta$$ = 0 and W is negative (volume decreases). Therefore q is negative i.e., gas releases heat. 'C' is correct.
For an isobaric process, V $$\propto$$ T i.e., we will get a straight inclined line in T-V graph. Therefore I and II are NOT isobaric. 'D' is correct.

Answer

Process $${\rm I}$$ is an isochoric process

Answer

In process $${\rm II}$$, gas absorbs heat

Answer

In process $${\rm IV}$$, gas releases heat

Answer

Process $${\rm I}$$ and $${\rm III}$$ are not isobaric

Thermodynamics & KTG

One mole of a monatomic ideal gas undergoes a cyclic process as shown in the figure (where $V is the volume and T$ is the temperature). Which of the statements below is (are) true?

Choose the correct answer: