Question 850: Thermodynamics & KTG

Question

For a gas, $$\frac{\mathrm{R}}{\mathrm{C}_{\mathrm{v}}}=0 \cdot 4$$, where $$\mathrm{R}$$ is universal gas constant and $$\mathrm{C}_{\mathrm{v}}$$ is molar specific heat at constant volume. The gas is made up of molecules which are

Accepted Answer

$$\begin{aligned}
& \quad 	ext { Given: } \frac{R}{C_V}=0.4 \
& C_V=\frac{R}{0.4}=\frac{5 R}{2} \
& C_P=C_V+R \
& 	herefore \quad C_P=\frac{7 R}{2} \
& \gamma=\frac{C_P}{C_v}=\frac{\frac{7}{5}}{\frac{5}{2}} \
& \gamma=\frac{7}{5}
\end{aligned}$$
$$	herefore \quad$$ The gas is made up of rigid diatomic molecules.

Answer

rigid diatomic

Answer

monoatomic

Answer

non-rigid diatomic

Answer

polyatomic

Thermodynamics & KTG

For a gas, $\frac{\mathrm{R}}{\mathrm{C}_{\mathrm{v}}}=0 \cdot 4, where \mathrm{R} is universal gas constant and \mathrm{C}_{\mathrm{v}}$ is molar specific heat at constant volume. The gas is made up of molecules which are

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