Question 973: Thermodynamics & KTG

Question

A container of volume $$200 \mathrm{~cm}^3$$ contains 0.2 mole of hydrogen gas and 0.3 mole of argon gas. The pressure of the system at temperature $$200 \mathrm{~K}$$ ($$\mathrm{R}=8.3 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}$$) will be :-

Accepted Answer

$$
\begin{aligned}
& P_{	ext {mix }}=\frac{\left(\mu_1+\mu_2ight) \mathrm{RT}_{	ext {mix }}}{\mathrm{V}_{	ext {mix }}} \
& =\frac{(0.2+0.3) 	imes 8.3 	imes 200}{200 	imes 10^{-6}} \
& =\frac{0.5 	imes 8.3 	imes 200}{200 	imes 10^{-6}} \
& \mathrm{P}_{	ext {mix }}=4.15 	imes 10^6 \mathrm{P}_{\mathrm{a}}
\end{aligned}
$$

Answer

$$6.15 	imes 10^5 \mathrm{~Pa}$$

Answer

$$6.15 	imes 10^4 \mathrm{~Pa}$$

Answer

$$4.15 	imes 10^5 \mathrm{~Pa}$$

Answer

$$4.15 	imes 10^6 \mathrm{~Pa}$$

Thermodynamics & KTG

A container of volume $200 \mathrm{~cm}^3 contains 0.2 mole of hydrogen gas and 0.3 mole of argon gas. The pressure of the system at temperature 200 \mathrm{~K} (\mathrm{R}=8.3 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}$) will be :-

Choose the correct answer: