Question 739: Thermodynamics & KTG

Question

The ratio of work done by an ideal rigid diatomic gas to the heat supplied by the gas in an isobaric process is

Accepted Answer

For an isobaric process involving an ideal rigid diatomic gas, the relationship between the heat supplied ($\Delta Q$) and the change in internal energy ($\Delta U$) can be expressed using the specific heat capacities at constant pressure ($C_p$) and constant volume ($C_v$):
$ \frac{\Delta Q}{\Delta U} = \frac{C_p}{C_v} = \frac{7}{5} $
Using the concept of dividendo, we get:
$ \frac{\Delta Q - \Delta U}{\Delta Q} = \frac{7 - 5}{7} = \frac{2}{7} $
This implies that the ratio of the work done by the gas ($W$) to the heat supplied ($\Delta Q$) in an isobaric process is:
$ \frac{W}{\Delta Q} = \frac{2}{7} $

Answer

$\frac{3}{7}$

Answer

$\frac{2}{7}$

Answer

$\frac{4}{7}$

Answer

$\frac{5}{7}$

Thermodynamics & KTG

The ratio of work done by an ideal rigid diatomic gas to the heat supplied by the gas in an isobaric process is

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