Question 290: Thermodynamics & KTG

Question

Heat energy of $735 \mathrm{~J}$ is given to a diatomic gas allowing the gas to expand at constant pressure.

Each gas molecule rotates around an internal axis but do not oscillate. The increase in the internal

energy of the gas will be :

Accepted Answer

$\Delta Q=n C_{P} \Delta T= $
$$n\left( {{f \over 2} + 1} ight)R\Delta T$$
= $$n\left( {{5 \over 2} + 1} ight)R\Delta T$$
= $$n\left( {{7 \over 2}} ight)R\Delta T$$
Given, $\Delta Q$ = 735
$$ \Rightarrow $$ $$n\left( {{7 \over 2}} ight)R\Delta T$$ = 735
$$ \Rightarrow $$ $$nR\Delta T = 735 	imes {2 \over 7}$$
Also, $$\Delta $$U = $${f \over 2}nR\Delta T$$
= $${5 \over 2}nR\Delta T$$
= $${5 \over 2} 	imes 735 	imes {2 \over 7}$$
= 525 J

Answer

$572 \mathrm{~J}$

Answer

$441 \mathrm{~J}$

Answer

$525 \mathrm{~J}$

Answer

$735 \mathrm{~J}$

Thermodynamics & KTG

Heat energy of 735 \mathrm{~J} is given to a diatomic gas allowing the gas to expand at constant pressure. Each gas molecule rotates around an internal axis but do not oscillate. The increase in the internal energy of the gas will be :

Choose the correct answer: