Question 296: Thermodynamics & KTG

Question

The pressure $$(\mathrm{P})$$ and temperature ($$\mathrm{T})$$ relationship of an ideal gas obeys the equation

$$\mathrm{PT}^{2}=$$ constant. The volume expansion coefficient of the gas will be :

Accepted Answer

$$PT^2$$ = constant
From $$PV = nRT \Rightarrow {{{T^3}} \over V} = $$ constant
$${T^3} \propto V$$ ..... (1)
$$3{T^2}dT \propto dV$$ ..... (2)
From (1) and (2)
$${{3dT} \over T} = {{dV} \over V}$$
$$	herefore$$ $$\gamma  = {1 \over V}{{dV} \over {dT}} = {3 \over T}$$

Answer

$$3 T^{2}$$

Answer

$$\frac{3}{T^2}$$

Answer

$$\frac{3}{T^3}$$

Answer

$$\frac{3}{T}$$

Thermodynamics & KTG

The pressure $(\mathrm{P}) and temperature (\mathrm{T}) relationship of an ideal gas obeys the equation \mathrm{PT}^{2}=$ constant. The volume expansion coefficient of the gas will be :

Choose the correct answer: