Question 839: Thermodynamics & KTG

Question

For polyatomic gases, the ratio of molar specific heat at constant pressure to constant volume is ( $$\mathrm{f}=$$ degrees of freedom)

Accepted Answer

For polyatomic gases, molar-specific heat at constant volume is $$\mathrm{C}_{\mathrm{V}}=(3+\mathrm{f}) \mathrm{R}$$ and Molar-specific heat at constant pressure is $$C_P=(4+f) R$$
$$	herefore \quad \frac{\mathrm{C}_{\mathrm{p}}}{\mathrm{C}_{\mathrm{V}}}=\frac{4+\mathrm{f}}{3+\mathrm{f}}$$

Answer

$$\frac{2+\mathrm{f}}{3+\mathrm{f}}$$

Answer

$$\frac{3+\mathrm{f}}{2+\mathrm{f}}$$

Answer

$$\frac{3+\mathrm{f}}{4+\mathrm{f}}$$

Answer

$$\frac{4+\mathrm{f}}{3+\mathrm{f}}$$

Thermodynamics & KTG

For polyatomic gases, the ratio of molar specific heat at constant pressure to constant volume is ( $\mathrm{f}=$ degrees of freedom)

Choose the correct answer: