Question 815: Thermodynamics & KTG

Question

The molecular mass of a gas having r.m.s. speed four times as that of another gas having molecular mass 32 is

Accepted Answer

$$\begin{array}{ll} 
& \mathrm{v}_{\mathrm{rms}} \propto \frac{1}{\sqrt{\mathrm{M}}} \
	herefore \quad & \frac{\left(\mathrm{v}_{\mathrm{rms}}ight)_2}{\left(\mathrm{v}_{\mathrm{rms}}ight)_1}=\sqrt{\frac{\mathrm{M}_1}{\mathrm{M}_2}} \
& 	ext { Given that }\left(\mathrm{v}_{\mathrm{rms}}ight)_2=4\left(\mathrm{v}_{\mathrm{rms}}ight)_1 \
	herefore \quad & \sqrt{\frac{32}{\mathrm{M}_2}}=4 \
	herefore \quad & \frac{32}{\mathrm{M}_2}=16 \
	herefore \quad & \mathrm{M}_2=2
\end{array}$$

Answer

2

Answer

4

Answer

16

Answer

32

Thermodynamics & KTG

The molecular mass of a gas having r.m.s. speed four times as that of another gas having molecular mass 32 is

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