Question 995: Thermodynamics & KTG

Question

A carnot engine having an efficiency of $${1 \over {10}}$$ as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is

Accepted Answer

Given, efficiency of engine, $$\eta  = {1 \over {10}}$$
work done on system  W = 10J
Coefficient of performance of refrigerator
$$\beta  = {{{Q_2}} \over W} = {{1 - \eta } \over \eta } = {{1 - {1 \over {10}}} \over {{1 \over {10}}}} = {{{9 \over {10}}} \over {{1 \over {10}}}} = 9$$
Energy absorbed from reservoir
$${Q_2} = \beta w$$
$${Q_2} = 9 	imes 10 = 90\,J$$

Answer

90 J

Answer

99 J

Answer

100 J

Answer

1 J

Thermodynamics & KTG

A carnot engine having an efficiency of ${1 \over {10}}$ as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is

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