Question 265: Oscillations

Question

The motion of a particle is described by the equation $a=-b x$ where ' $a$ ' is the acceleration, x is the displacement from the equilibrium position and b is a constant. The periodic time will be

Accepted Answer

Given, $\mathrm{a}=-\mathrm{bx}$
But, $a=-\omega^2 x$
$$\begin{aligned}
	herefore \quad \omega & =\sqrt{\mathrm{b}} \quad	ext{.... (i)}\
\mathrm{~T} & =\frac{2 \pi}{\omega} \
& =\frac{2 \pi}{\sqrt{\mathrm{~b}}} \quad	ext{...[From(i)]}
\end{aligned}$$

Answer

$\frac{2 \pi}{\mathrm{~b}}$

Answer

$\frac{2 \pi}{\sqrt{b}}$

Answer

$2 \pi \sqrt{b}$

Answer

$2 \sqrt{\frac{\pi}{b}}$

Oscillations

The motion of a particle is described by the equation a=-b x where ' a ' is the acceleration, x is the displacement from the equilibrium position and b is a constant. The periodic time will be

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