Question 325: Oscillations

Question

In a medium, the phase difference between two particles separated by a distance '$$x$$' is $$\left(\frac{\pi}{5}ight)^{	ext {c }}$$. If the frequency of the oscillation of particles is $$25 \mathrm{~Hz}$$ and the velocity of propagation of the waves is $$75 \mathrm{~m} / \mathrm{s}$$, then the value of $$x$$ is

Accepted Answer

$$\begin{aligned}
& 	ext { } \lambda=\frac{\mathrm{v}}{\mathrm{n}}=\frac{75}{25}=3 \mathrm{~m} \
& 	ext { and phase difference }=\frac{2 \pi}{\lambda} 	ext { (path difference) } \
& 	herefore \frac{\pi}{5}=\frac{2 \pi}{3} \mathrm{x} \
& 	herefore 10 \mathrm{x}=3 \
& 	herefore \mathrm{x}=\frac{3}{10}=0.3 \mathrm{~m}
\end{aligned}$$

Answer

0.4 m

Answer

0.1 m

Answer

0.2 m

Answer

0.3 m

Oscillations

In a medium, the phase difference between two particles separated by a distance '$x' is \left(\frac{\pi}{5}\right)^{\text {c }}. If the frequency of the oscillation of particles is 25 \mathrm{~Hz} and the velocity of propagation of the waves is 75 \mathrm{~m} / \mathrm{s}, then the value of x$ is

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