Question 143: Oscillations

Question

A particle is executing simple harmonic motion with a time period T. At time t = 0, it is at its position of
equilibrium. The kinetic energy – time graph of the particle will look like:

Accepted Answer

For a particle executing SHM
At mean position; t = 0, $$\omega $$t = 0, y = 0, V = V
max
= a$$\omega $$
$$ 	herefore $$ K.E = K.E
max
= $${1 \over 2}m{\omega ^2}{a^2}$$
At extreme position : t =
$${T \over 4}$$
, $$\omega $$t =
$${\pi  \over 2}$$
, y = A, V = V
min
= 0
$$ 	herefore $$ K.E = K.E
min
= 0
Hence graph (A) correctly represents kinetic energy - time graph.

Answer

Answer

Answer

Answer

Oscillations

A particle is executing simple harmonic motion with a time period T. At time t = 0, it is at its position of equilibrium. The kinetic energy – time graph of the particle will look like:

Choose the correct answer: