Question 166: Oscillations

Question

If a simple harmonic motion is represented by $${{{d^2}x} \over {d{t^2}}} + \alpha x = 0.$$ its time period is

Accepted Answer

$${{{d^2}x} \over {d{t^2}}} =  - \alpha x =  - {\omega ^2}x$$
$$ \Rightarrow \omega  = \sqrt \alpha  $$ $$\,\,\,\,$$ or $$\,\,\,\,$$ $$T = {{2\pi } \over \omega } = {{2\pi } \over {\sqrt \alpha  }}$$

Answer

$${{2\pi } \over {\sqrt \alpha  }}$$

Answer

$${{2\pi } \over \alpha }$$

Answer

$$2\pi \sqrt \alpha  $$

Answer

$$2\pi \alpha $$

Oscillations

If a simple harmonic motion is represented by ${{{d^2}x} \over {d{t^2}}} + \alpha x = 0.$ its time period is

Choose the correct answer: