Question 297: Oscillations

Question

Choose the correct answer.
When a point of suspension of pendulum is moved vertically upward with acceleration ' $a$ ', its period of oscillation

Accepted Answer

For a simple pendulum,
$$\mathrm{T}=2 \pi \sqrt{\frac{l}{\mathrm{~g}}} \Rightarrow \mathrm{~T} \propto \frac{1}{\mathrm{~g}}$$
When the point of suspension is moved vertically upwards with acceleration a, $g$ becomes $g+a$. Hence, T decreases.

Answer

decreases

Answer

increases

Answer

remains same

Answer

some times increases and some times decreases

Oscillations

Choose the correct answer. When a point of suspension of pendulum is moved vertically upward with acceleration ' a ', its period of oscillation

Choose the correct answer: