Question 383: Waves

Question

A string fixed at both the ends forms standing wave with node separation of $$5 \mathrm{~cm}$$. If the velocity of the wave on the string is $$2 \mathrm{~m} / \mathrm{s}$$, then the frequency of vibration of the string is

Accepted Answer

Separation between consecutive nodes, $$\frac{\lambda}{2}=5 \mathrm{~cm}$$
$$	herefore \quad \lambda=10 \mathrm{~cm}=0.1 \mathrm{~m}$$
The frequency of vibration is given as:
$$\mathrm{n}=\frac{\mathrm{v}}{\lambda}=\frac{2}{0.1}=20 \mathrm{~Hz}$$

Answer

0.2 Hz

Answer

10 Hz

Answer

20 Hz

Answer

40 Hz

Waves

A string fixed at both the ends forms standing wave with node separation of $5 \mathrm{~cm}. If the velocity of the wave on the string is 2 \mathrm{~m} / \mathrm{s}$, then the frequency of vibration of the string is

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