Question 361: Waves

Question

If '$$l$$' is the length of the open pipe, '$$r$$' is the internal radius of the pipe and '$V$ ' is the velocity of sound in air then fundamental frequency of open pipe is

Accepted Answer

For an open organ pipe, the length of the pipe with end correction is given as:
$$\begin{aligned}
& \mathrm{L}=l+2 \mathrm{e}=l+2 	imes 0.6 \mathrm{r} \
& \mathrm{L}=l+1.2 \mathrm{r}
\end{aligned}$$
$$	herefore$$ The fundamental frequency of open pipe is:
$$\begin{aligned}
& \mathrm{f}=\frac{\mathrm{v}}{2 \mathrm{~L}} \
& \mathrm{f}=\frac{\mathrm{v}}{2(l+1.2 \mathrm{r})}
\end{aligned}$$

Answer

$$\frac{\mathrm{V}}{(l+0.3 \mathrm{r})}$$

Answer

$$\frac{\mathrm{V}}{(l+1.2 \mathrm{r})}$$

Answer

$$\frac{\mathrm{V}}{(l+0.6 \mathrm{r})}$$

Answer

$$\frac{\mathrm{V}}{2(l+1.2 \mathrm{r})}$$

Waves

If '$l' is the length of the open pipe, 'r' is the internal radius of the pipe and 'V$ ' is the velocity of sound in air then fundamental frequency of open pipe is

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