Question 376: Waves

Question

41 tuning forks are arranged in increasing order of frequency such that each produces 5 beats/second with next tuning fork. If frequency of last tuning fork is double that of frequency of first fork. Then frequency of first and last fork is

Accepted Answer

Let Frequency of $$1^{	ext {st }}$$ tuning fork be $$=\mathrm{n}_1$$
$$	herefore \quad$$ frequency of $$41^{	ext {st }}$$ tuning fork $$=\mathrm{n}_{41}$$
Now,
$$\begin{array}{ll} 
& \mathrm{n}_{41}=\mathrm{n}_1+(41-1) 	imes 5 \
& 	ext { But, } \mathrm{n}_{41}=2 \mathrm{n}_1 \
	herefore \quad & 2 \mathrm{n}_1=\mathrm{n}_1+200 \
	herefore \quad & \mathrm{n}_1=200 \mathrm{~Hz} \
	herefore \quad & \mathrm{n}_{41}=400 \mathrm{~Hz}
\end{array}$$

Answer

$$400,200 \mathrm{~Hz}$$

Answer

$$200,400 \mathrm{~Hz}$$

Answer

$$100,200 \mathrm{~Hz}$$

Answer

$$205,410 \mathrm{~Hz}$$

Waves

41 tuning forks are arranged in increasing order of frequency such that each produces 5 beats/second with next tuning fork. If frequency of last tuning fork is double that of frequency of first fork. Then frequency of first and last fork is

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