Question 339: Waves

Question

If ' $l$ ' is the length of pipe, ' $r$ ' is the internal radius of the pipe and ' $v$ ' is the velocity of sound in air then fundamental frequency of open pipe is

Accepted Answer

For an open organ pipe, the effective length of the pipe, taking end correction into account, is calculated as follows:
$  L = l + 2e = l + 2 	imes 0.6r  $
Since $ e = 0.6r $ for an open pipe, this simplifies to:
$  L = l + 1.2r  $
Therefore, the fundamental frequency of the open pipe is expressed as:
$  f = \frac{v}{2L} = \frac{v}{2(l + 1.2r)}  $
Here, $ v $ is the velocity of sound in air, $ l $ is the length of the pipe, and $ r $ is the internal radius of the pipe.

Answer

$\frac{\mathrm{V}}{2(l+1 \cdot 2 \mathrm{r})}$

Answer

$\frac{\mathrm{V}}{(l+1 \cdot 2 \mathrm{r})}$

Answer

$\frac{\mathrm{V}}{(l+0.3 \mathrm{r})}$

Answer

$\frac{\mathrm{V}}{(l+0 \cdot 6 \mathrm{r})}$

Waves

If ' l ' is the length of pipe, ' r ' is the internal radius of the pipe and ' v ' is the velocity of sound in air then fundamental frequency of open pipe is

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