Question 354: Waves

Question

Sound waves of frequency $$600 \mathrm{~Hz}$$ fall normally on a perfectly reflecting wall. The shortest distance from the wall at which all particles will have maximum amplitude of vibration is (speed of sound $$=300 \mathrm{~ms}^{-1}$$ )

Accepted Answer

The maximum displacement of the wave will occur at antinode of the wave. The first antinode will be a point where, $$d=\frac{\lambda}{4}$$
The wavelength is given by,
$$\lambda=\frac{\mathrm{v}}{\mathrm{f}}=\frac{300}{600}$$
So, $$d=\frac{0.5}{4}=\frac{1}{8} \mathrm{~m}$$

Answer

$$\frac{1}{4} \mathrm{~m}$$

Answer

$$\frac{1}{8} \mathrm{~m}$$

Answer

$$\frac{3}{8} \mathrm{~m}$$

Answer

$$\frac{7}{8} \mathrm{~m}$$

Waves

Sound waves of frequency $600 \mathrm{~Hz} fall normally on a perfectly reflecting wall. The shortest distance from the wall at which all particles will have maximum amplitude of vibration is (speed of sound =300 \mathrm{~ms}^{-1}$ )

Choose the correct answer: