Question 518: Waves

Question

The phase difference between two waves. represented by
y1 = 10$$-$$6 sin[100t + (x/50) + 0.5] m
y2 = 10$$-$$6 cos[100t + (x/50)] m,
where x is expressed in metres and t is exressed in secondss, is approximately.

Accepted Answer

y
1
= 10
Ã¢ÂÂ6
sin[100t + (x/50) + 0.5]
y
2
= 10
Ã¢ÂÂ6
cos[100t + (x/50)]
[using cosx = sin(x + $$\pi $$/2)]
= 10
Ã¢ÂÂ6
sin[100t + (x/50) + $$\pi $$/2]
= 10
Ã¢ÂÂ6
sin[100t + (x/50) + 1.57]
The phase difference = 1.57 Ã¢ÂÂ 0.5 = 1.07
[or using sinx = cos($$\pi $$/2 Ã¢ÂÂ x). We get the same result.]

Answer

1.07 radians

Answer

2.07 radians

Answer

0.5 radians

Answer

1.5 radians

Waves

The phase difference between two waves. represented by y1 = 10$-6 sin[100t + (x/50) + 0.5] m y2 = 10-$6 cos[100t + (x/50)] m, where x is expressed in metres and t is exressed in secondss, is approximately.

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