Question 435: Waves

Question

In fundamental mode, the time required for the sound wave to reach upto the closed end of pipe filled with air is $$t$$ second. The frequency of vibration of air column is

Accepted Answer

In fundamental mode the length of the closed tube is $$\frac{\lambda}{4}$$
Time required to travel a distance $$\frac{\lambda}{4}$$ is t.
Hence time required to travel a distance $$\lambda$$ will be $$4 \mathrm{t}$$.
$$	herefore$$ Time period $$\mathrm{T}=4 \mathrm{t}$$;
Frequency $$\mathrm{n}=\frac{1}{\mathrm{~T}}=\frac{1}{4 \mathrm{t}}=\frac{0.25}{\mathrm{t}}$$

Answer

$$\frac{1}{t}$$

Answer

$$\frac{2}{t}$$

Answer

$$\frac{3}{t}$$

Answer

$$\frac{0.25}{\mathrm{t}}$$

Waves

In fundamental mode, the time required for the sound wave to reach upto the closed end of pipe filled with air is $t$ second. The frequency of vibration of air column is

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