Question 264: Waves

Question

Two waves of same frequency ( n ) are approaching each other with same velocity $12 \mathrm{~m} / \mathrm{s}$ along the same linear path and interfere. The distance between two consecutive nodes is

Accepted Answer

Step 1: Recall standing wave condition
When two identical waves travel in opposite directions with same frequency and amplitude, a standing wave is formed.
The distance between two consecutive nodes in a standing wave is
half of the wavelength
($\lambda/2$).
Step 2: Relating wavelength and wave speed
General wave relation:
$ v = n \lambda $
Given:
$ v = 12 \,	ext{m/s}, \quad 	ext{frequency} = n \,	ext{Hz} $
So:
$ \lambda = \frac{v}{n} = \frac{12}{n} $
Step 3: Distance between consecutive nodes
$ d = \frac{\lambda}{2} = \frac{1}{2}\cdot\frac{12}{n} = \frac{6}{n} $
Final Answer:
$ \boxed{\frac{6}{n}} $
Correct option: D

Answer

12 n

Answer

$\frac{12}{n}$

Answer

6 n

Answer

$\frac{6}{n}$

Waves

Two waves of same frequency ( n ) are approaching each other with same velocity 12 \mathrm{~m} / \mathrm{s} along the same linear path and interfere. The distance between two consecutive nodes is

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