Question 398: Current Electricity

Question

Twelve wires each having resistance $$2 \Omega$$ are joined to form a cube. A battery of $$6 \mathrm{~V}$$ emf is joined across point $$a$$ and $$c$$. The voltage difference between $$e$$ and $$f$$ is ________ V.

Accepted Answer

The circuit can be simplified as
$$\begin{aligned}
& R_{a c}=\frac{6 	imes 2}{8}=\frac{3}{2} \Omega \
& \begin{aligned}
& i=1 \mathrm{Amp} . \
& V_{e f}=\left(\frac{i}{2}ight)^2 \
& \quad=1 \mathrm{~V}
\end{aligned}
\end{aligned}$$

Current Electricity

Twelve wires each having resistance $2 \Omega are joined to form a cube. A battery of 6 \mathrm{~V} emf is joined across point a and c. The voltage difference between e and f$ is ________ V.

Choose the correct answer: