Question 494: Current Electricity

Question

The equivalent resistance of the following circuit when no current flows in the resistance of $5 \Omega$ is nearly

Accepted Answer

As no current flows through the $5 \Omega$, the circuit is a wheatstone bridge. The effective resistance of arms AB and BC is $\mathrm{R}_1=10+15=25 \Omega$
and,
The effective resistance of arms AD and CD is: $\mathrm{R}_2=20+30=50 \Omega$
$R_1$ and $R_2$ will be in parallel.
$	herefore$ The equivalent resistance of the circuit is: $\mathrm{R}=\frac{\mathrm{R}_1 \mathrm{R}_2}{\mathrm{R}_1+\mathrm{R}_2}=\frac{25 	imes 50}{25+50}=16.66 \Omega \mathrm{R} \approx 17 \Omega$

Answer

$13 \Omega$

Answer

$17 \Omega$

Answer

$19 \Omega$

Answer

$21 \Omega$

Current Electricity

The equivalent resistance of the following circuit when no current flows in the resistance of 5 \Omega is nearly

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