Question 543: Current Electricity

Question

The current flowing in a coil is 3 A and the power consumed is 108 W . If the a.c. source is of $120 \mathrm{~V}, 50 \mathrm{~Hz}$, the resistance in the circuit is

Accepted Answer

To find the resistance in the circuit, use the formula for power in terms of resistance, current, and voltage:
$$ P = I^2 R $$
Where:
$ P $ is the power consumed (108 W),
$ I $ is the current flowing through the coil (3 A),
$ R $ is the resistance we need to find.
Rearrange the formula to solve for $ R $:
$$ R = \frac{P}{I^2} $$
Now substitute the known values:
$$ R = \frac{108 \, 	ext{W}}{(3 \, 	ext{A})^2} = \frac{108}{9} = 12 \, \Omega $$
Therefore, the resistance in the circuit is $ 12 \, \Omega $.
Correct Option: C) $ 12 \Omega $

Answer

$24 \Omega$

Answer

$36 \Omega$

Answer

$12 \Omega$

Answer

$6 \Omega$

Current Electricity

The current flowing in a coil is 3 A and the power consumed is 108 W . If the a.c. source is of 120 \mathrm{~V}, 50 \mathrm{~Hz}, the resistance in the circuit is

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