Question 633: Current Electricity

Question

The equivalent resistance of the infinite network given below is :

Accepted Answer

Let net resistance of the given infinite network be 'R'
Now, the circuit can be modified as
Now, $${R_{net}} = R = 1 + 1 + {R \over {R + 1}}$$
$$	herefore$$ $$R = 2 + {R \over {R + 1}}$$
$${R^2} + R = 2R + 2 + R$$
$${R^2} - 2R - 2 = 0$$
$$R = \left( {{{2\, \pm \,\sqrt {4 + 8} } \over 2}} ight)$$
$$R = \left( {1 + \sqrt 3 } ight)\Omega $$

Answer

$$\left( {1 + \sqrt 5 } \right)\Omega $$

Answer

$$2\,\Omega $$

Answer

$$\left( {1 + \sqrt 2 } \right)\Omega $$

Answer

$$\left( {1 + \sqrt 3 } \right)\Omega $$

Current Electricity

The equivalent resistance of the infinite network given below is :

Choose the correct answer: