Question 312: Current Electricity

Question

Two batteries with e.m.f 12 V and 13 V are connected in parallel across a load resistor of 10 $$\Omega $$. The
internal resistances of the two batteries are 1 $$\Omega $$ and 2 $$\Omega $$ respectively. The voltage across the load lies between :

Accepted Answer

Let potential at S, T, R = V and potential at P, Q, U, = 0
Using kirchhoff's law at P :
Current at P is ,
$${{V - 12} \over 1} + {{V - 13} \over 2} + {{V - 0} \over {10}} = 0$$
$$ \Rightarrow $$$$\,\,\,$$ $${V \over 1}$$ + $${V \over 2}$$ + $${V \over 10}$$ = 12 + $${{13} \over 2}$$
$$ \Rightarrow $$$$\,\,\,$$ $${{10V + 5V + V} \over {10}}$$ = $${{37} \over 2}$$
$$ \Rightarrow $$$$\,\,\,$$ $${{16V} \over {10}}$$ = $${{37} \over 2}$$
$$ \Rightarrow $$$$\,\,\,$$ V = 11.56 Volt.

Answer

11.7 V and 11.8 V

Answer

11.6 V and 11.7 V

Answer

11.5 V and 11.6 V

Answer

11.4 V and 11.5 V

Current Electricity

Two batteries with e.m.f 12 V and 13 V are connected in parallel across a load resistor of 10 $\Omega . The internal resistances of the two batteries are 1 \Omega and 2 \Omega $ respectively. The voltage across the load lies between :

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