Question 596: Current Electricity

Question

A 10 m long wire of resistance $20 \Omega$ is connected in series with a battery of emf 3 V and a resistance of $10 \Omega$. The potential gradient along the wire in $\mathrm{V} / \mathrm{m}$ is

Accepted Answer

The equivalent resistance of the circuit,
$$R_{\mathrm{eq}}=20+10=30 \Omega$$
The current flowing through the wire,
$$i=\frac{V}{R}=\frac{3 \mathrm{~V}}{30 \Omega}=0.1 \mathrm{~A}$$
The potential gradient along the wire,
$$\begin{aligned}
& =\frac{	ext { Potential difference across } 20 \Omega}{	ext { Length of } 20 \Omega 	ext { wire }} \
& =\frac{0.1 	imes 20 \Omega}{10 \mathrm{~m}}=0.20 \mathrm{~V} / \mathrm{m}
\end{aligned}$$

Answer

1.2

Answer

0.10

Answer

0.02

Answer

0.20

Current Electricity

A 10 m long wire of resistance 20 \Omega is connected in series with a battery of emf 3 V and a resistance of 10 \Omega. The potential gradient along the wire in \mathrm{V} / \mathrm{m} is

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