Question 592: Current Electricity

Question

A galvanometer of resistance $$50 \Omega$$ is converted to an ammeter. After shunting, the effective resistance of ammeter is $$2.5 \Omega$$. The value of shunt is

Accepted Answer

The resistance of the galvanometer and the shunt are in parallel. Their equivalent resistance is given by
$$\begin{array}{rlrl} 
& \frac{1}{R}=\frac{1}{G}+\frac{1}{S} \
	herefore  \frac{1}{S} & =\frac{1}{R}-\frac{1}{G} \
	herefore  \frac{1}{S} & =\frac{1}{2.5}-\frac{1}{50}=\frac{19}{50} \quad 	herefore S=\frac{50}{19} \Omega\end{array}$$

Answer

$$\frac{100}{19} \Omega$$

Answer

$$\frac{50}{19} \Omega$$

Answer

$$\frac{25}{19} \Omega$$

Answer

$$\frac{75}{19} \Omega$$

Current Electricity

A galvanometer of resistance $50 \Omega is converted to an ammeter. After shunting, the effective resistance of ammeter is 2.5 \Omega$. The value of shunt is

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