Question 266: Current Electricity

Question

The resistive network shown below is connected to a D.C. source of 16 V. The power consumed by the
network is 4 Watt. The value of R is:

Accepted Answer

R
eq
= 2R + R + 4R + R = 8R
$$P = {{{v^2}} \over {{R_{eq}}}} \Rightarrow {{16 	imes 16} \over {8R}} = 4\,watt$$
$${{16 	imes 16} \over {4 	imes 8}} = R \Rightarrow R = 8\Omega $$

Answer

16 $$\Omega $$

Answer

1 $$\Omega $$

Answer

8 $$\Omega $$

Answer

6 $$\Omega $$

Current Electricity

The resistive network shown below is connected to a D.C. source of 16 V. The power consumed by the network is 4 Watt. The value of R is:

Choose the correct answer: