Question 234: Current Electricity

Question

In the given figure, there is a circuit of potentiometer of length AB = 10 m. The resistance per unit length is 0.1 $$\Omega$$ per cm. Across AB, a battery of emf E and internal resistance 'r' is connected. The maximum value of emf measured by this potentiometer is :

Accepted Answer

Max. voltage that can be measured by this potentiometer will be equal to potential drop across AB
R
AB
= 10 $$	imes$$ 0.1 $$	imes$$ 100 = 100 ohm.
$$	herefore$$ $${V_{AB}} = {6 \over {20 + 100}} 	imes 100 = 6 	imes {{100} \over {120}} = 5$$ V

Answer

5 V

Answer

2.25 V

Answer

6 V

Answer

2.75 V

Current Electricity

In the given figure, there is a circuit of potentiometer of length AB = 10 m. The resistance per unit length is 0.1 $\Omega$ per cm. Across AB, a battery of emf E and internal resistance 'r' is connected. The maximum value of emf measured by this potentiometer is :

Choose the correct answer: