Question 195: Current Electricity

Question

A cell of emf 90 V is connected across series combination of two resistors each of 100$$\Omega$$ resistance. A voltmeter of resistance 400$$\Omega$$ is used to measure the potential difference across each resistor. The reading of the voltmeter will be :

Accepted Answer

$$
\begin{aligned}
& \mathrm{R}_{\mathrm{eq}}=\frac{400 	imes 100}{500}+100 \\
& =180 \Omega \\
& \mathrm{i}=\frac{90}{180}=\frac{1}{2} \mathrm{~A} \\
& 	ext { Reading }=\frac{1}{2} 	imes \frac{400 	imes 100}{500} \\
& =40 	ext { volt }
\end{aligned}
$$

Answer

40 V

Answer

90 V

Answer

45 V

Answer

80 V

Current Electricity

A cell of emf 90 V is connected across series combination of two resistors each of 100$\Omega resistance. A voltmeter of resistance 400\Omega$ is used to measure the potential difference across each resistor. The reading of the voltmeter will be :

Choose the correct answer: