Question 238: Current Electricity

Question

In the experiment of Ohm's law, a potential difference of 5.0 V is applied across the end of a conductor of length 10.0 cm and diameter of 5.00 mm. The measured current in the conductor is 2.00 A. The maximum permissible percentage error in the resistivity of the conductor is :

Accepted Answer

$$V = I 	imes ho {l \over A}$$
$$ \Rightarrow ho  = {{VA} \over {Il}} = {\pi  \over 4}{{V{d^2}} \over {Il}}$$
$${{\Delta ho } \over ho } = {{2\Delta d} \over d} + {{\Delta V} \over V} + {{\Delta I} \over I} + {{\Delta l} \over l}$$
$$ = 2\left( {{{0.01} \over 5}} ight) + {{0.1} \over 5} + {{0.01} \over 2} + {{0.1} \over {10}}$$
$$ \Rightarrow $$ $${{\Delta ho } \over ho } = 0.039 = 3.9\% $$

Answer

3.9

Answer

8.4

Answer

7.5

Answer

3.0

Current Electricity

In the experiment of Ohm's law, a potential difference of 5.0 V is applied across the end of a conductor of length 10.0 cm and diameter of 5.00 mm. The measured current in the conductor is 2.00 A. The maximum permissible percentage error in the resistivity of the conductor is :

Choose the correct answer: