Question 277: Current Electricity

Question

A metal wire of resistance 3 $$\Omega $$  is elongated to
make a uniform wire of double its previous
length. This new wire is now bent and the ends
joined to make a circle. If two points on this
circle make an angle 60° at the centre, the
equivalent resistance between these two points
will be :-

Accepted Answer

$$R = {{ho l} \over A} = {{ho l} \over {\left( {V/l} ight)}} = {{ho {l^2}} \over V}\left( {V{m{ }} 	o {m{ }}Volume{m{ }}\,of{m{ }}\,wire} ight)$$
$$ \Rightarrow $$ Final resistance = 3 ÃÂ (B)
2
= 12 $$\Omega $$
$${R_{eq}} = 2\Omega \parallel 10\Omega  = {5 \over 3}\Omega $$

Answer

5 /2 $$\Omega $$

Answer

12/5 $$\Omega $$

Answer

7/2 $$\Omega $$

Answer

5 / 3 $$\Omega $$

Current Electricity

A metal wire of resistance 3 $\Omega $ is elongated to make a uniform wire of double its previous length. This new wire is now bent and the ends joined to make a circle. If two points on this circle make an angle 60° at the centre, the equivalent resistance between these two points will be :-

Choose the correct answer: