Question 686: Current Electricity

Question

The mean free path of electrons in a metal is 4 $$ 	imes $$ 10$$-$$8 m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units V/m

Accepted Answer

Given, Energy = 2 eV = eE$$\lambda $$
$$ 	herefore $$ E = $${{2eV} \over {e\lambda }} = {2 \over {4 	imes {{10}^{ - 8}}}} = 5 	imes {10^7}$$ V/m

Answer

$$5 	imes {10^{ - 11}}$$

Answer

8 $$ 	imes $$  10$$-$$11

Answer

5 $$ 	imes $$ 107

Answer

8 $$ 	imes $$ 107

Current Electricity

The mean free path of electrons in a metal is 4 $ \times 10-$8 m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units V/m

Choose the correct answer: