Question 146: Current Electricity

Question

The number of electrons flowing per second in the filament of a $$110 \mathrm{~W}$$ bulb operating at $$220 \mathrm{~V}$$ is : (Given $$\mathrm{e}=1.6 	imes 10^{-19} \mathrm{C}$$)

Accepted Answer

$$\begin{aligned}
& P=v 	imes i \Rightarrow i=\frac{110}{220}=\frac{1}{2} \mathrm{~A} \
& i=n e \Rightarrow n=\frac{1}{2 	imes 1.6 	imes 10^{-19}}=31.25 	imes 10^{17}
\end{aligned}$$

Answer

$$1.25 	imes 10^{19}$$

Answer

$$31.25 	imes 10^{17}$$

Answer

$$6.25 	imes 10^{18}$$

Answer

$$6.25 	imes 10^{17}$$

Current Electricity

The number of electrons flowing per second in the filament of a $110 \mathrm{~W} bulb operating at 220 \mathrm{~V} is : (Given \mathrm{e}=1.6 \times 10^{-19} \mathrm{C}$)

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