Question 11: Magnetism and Matter

Question

The relationship between the magnetic susceptibility $(x)$ and the magnetic permeability $(\mu)$ is given by :
( $\mu_0$ is the permeability of free space and $\mu_T$ is relative permeability)

Accepted Answer

The relationship between magnetic susceptibility $(\chi)$ and magnetic permeability $(\mu)$ is expressed as follows:
Relative Permeability ($\mu_r$)
: This is defined as the ratio of the permeability of a material ($\mu$) to the permeability of free space ($\mu_0$).
$    \mu = \mu_0 \mu_r \Rightarrow \mu_r = \frac{\mu}{\mu_0}    $
Magnetic Susceptibility ($\chi$)
: This relates to relative permeability as follows:
$    \mu_r = 1 + \chi \Rightarrow \chi = \mu_r - 1    $
Substituting the expression for $\mu_r$ from above:
$    \chi = \left(\frac{\mu}{\mu_0} - 1\right)    $
Thus, the equation shows how magnetic susceptibility is derived from the magnetic permeability relative to free space.

Answer

$X=\frac{\mu}{\mu_0}-1$

Answer

$X=\frac{\mu_{\mathrm{r}}}{\mu_0}+1$

Answer

$\chi=\mu_r+1$

Answer

$X=1-\frac{\mu}{\mu_0}$

Magnetism and Matter

The relationship between the magnetic susceptibility (x) and the magnetic permeability (\mu) is given by : ( \mu_0 is the permeability of free space and \mu_T is relative permeability)

Choose the correct answer: