Question 190: Magnetism and Matter

Question

Find the magnetic field at point P due to a straight line segment AB of length 6 cm carrying a current of 5A.
(See figure) ($$\mu $$0 = 4$$\pi $$ × 10–7 N-A–2)

Accepted Answer

B = $${{{\mu _0}I} \over {4\pi r}}\left( {\sin {	heta _1} + \sin {	heta _2}} ight)$$
As $$	heta $$
1
= $$	heta $$
2
= $$	heta $$
B = $${{{\mu _0}I} \over {4\pi r}}\left( {2\sin 	heta } ight)$$
= $${{{{10}^{ - 7}} 	imes 5} \over {4 	imes {{10}^{ - 2}}}} 	imes 2 	imes {3 \over 5}$$
= 1.5 $$ 	imes $$ 10
-5
T

Answer

1.5 × 10–5
 T

Answer

3.0 × 10–5
 T

Answer

2.0 × 10–5
 T

Answer

2.5 × 10–5
 T

Magnetism and Matter

Find the magnetic field at point P due to a straight line segment AB of length 6 cm carrying a current of 5A. (See figure) ($\mu 0 = 4\pi $ × 10–7 N-A–2)

Choose the correct answer: