Question 188: Magnetism and Matter

Question

Photon with kinetic energy of 1MeV moves
from south to north. It gets an acceleration of
1012 m/s2 by an applied magnetic field (west to
east). The value of magnetic field : (Rest mass
of proton is 1.6 × 10–27 kg) :

Accepted Answer

K.E = $${1 \over 2}m{v^2}$$
$$ \Rightarrow $$ 1 MeV = $${1 \over 2}m{v^2}$$
$$ \Rightarrow $$ 1.6 $$ 	imes $$ 10
-19
$$ 	imes $$ 10
6
= $${1 \over 2}$$ $$ 	imes $$ 1.6 ÃÂ 10
Ã¢ÂÂ27
$$ 	imes $$ v
2
$$ \Rightarrow $$ v = $$\sqrt 2  	imes {10^7}$$ m/s
F
m
= qvB sin$$	heta $$
$$ \Rightarrow $$ F
m
= qvB [as $$	heta $$ = 90
o
]
$$ \Rightarrow $$ ma = Bev
$$ \Rightarrow $$ 1.6 ÃÂ 10
Ã¢ÂÂ27
$$ 	imes $$ 10
12
= 1.6 $$ 	imes $$ 10
-19
$$ 	imes $$ $$\sqrt 2  	imes {10^7}$$ $$ 	imes $$ B
$$ \Rightarrow $$ B = 0.71 mJ

Answer

0.71mT

Answer

7.1mT

Answer

0.071mT

Answer

71mT

Magnetism and Matter

Photon with kinetic energy of 1MeV moves from south to north. It gets an acceleration of 1012 m/s2 by an applied magnetic field (west to east). The value of magnetic field : (Rest mass of proton is 1.6 × 10–27 kg) :

Choose the correct answer: