Question 312: Electromagnetic Induction

Question

. If the current of '$$I$$' A gives rise to a magnetic flux '$$\phi$$' through a coil having '$$N$$' turns then mangetic energy stored in the medium surrounding the coil is

Accepted Answer

To determine the magnetic energy stored in the medium surrounding the coil, we need to use the relationship between the magnetic flux, current, number of turns in the coil, and the energy stored in the magnetic field.
Magnetic energy stored in an inductor (coil) is given by the formula:
$$  	ext{Magnetic Energy} = \frac{1}{2} L I^2  $$
where:
$$L$$ is the inductance of the coil.
$$I$$ is the current through the coil.
According to the definition of inductance:
$$  L = \frac{N \phi}{I}  $$
where:
$$N$$ is the number of turns in the coil.
$$\phi$$ is the magnetic flux through the coil.
Now, substituting the expression for $$L$$ in the energy formula:
$$  	ext{Magnetic Energy} = \frac{1}{2} \left( \frac{N \phi}{I} ight) I^2  $$
Simplifying this expression:
$$  	ext{Magnetic Energy} = \frac{1}{2} N \phi I  $$
Therefore, the magnetic energy stored in the medium surrounding the coil is:
$$  \frac{N \phi I}{2}  $$
The correct option is:
Option B: $$\frac{\mathrm{N} \phi \mathrm{I}}{2}$$

Answer

$$\frac{\mathrm{N} \phi \mathrm{I}}{4}$$

Answer

$$\frac{\mathrm{N} \phi \mathrm{I}}{2}$$

Answer

$$\frac{\mathrm{NI}}{2 \phi}$$

Answer

$$\frac{\mathrm{N} \phi}{2 \mathrm{I}}$$

Electromagnetic Induction

. If the current of '$I' A gives rise to a magnetic flux '\phi' through a coil having 'N$' turns then mangetic energy stored in the medium surrounding the coil is

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