Question 308: Electromagnetic Induction

Question

A current 'I' produces a magnetic flux '$$\phi$$' per turn in a coil of '$$n$$' turns. Self inductance of the coil is '$$L$$'. The relation between them is

Accepted Answer

To determine the relationship between the current $$I$$, magnetic flux $$\phi$$, and self-inductance $$L$$ for a coil with $$n$$ turns, we start with the definition of self-inductance. Self-inductance $$L$$ of a coil is given by:
$$ L = \frac{N \cdot \phi}{I} $$
where $$N$$ is the number of turns, $$\phi$$ is the magnetic flux through the coil, and $$I$$ is the current. In our case, $$N$$ is $$n$$. Therefore, this becomes:
$$ L = \frac{n \cdot \phi}{I} $$
Rearranging this formula to isolate $$\phi$$ on one side, we get:
$$ \phi = \frac{L \cdot I}{n} $$
Thus, the correct relationship is:
Option D: $$\frac{\mathrm{LI}}{\mathrm{n}}=\phi$$

Answer

$$\mathrm{nLI}=\phi$$

Answer

$$\frac{\mathrm{nL}}{\mathrm{I}}=\phi$$

Answer

$$\frac{\mathrm{LI}}{\mathrm{n}^2}=\phi$$

Answer

$$\frac{\mathrm{LI}}{\mathrm{n}}=\phi$$

Electromagnetic Induction

A current 'I' produces a magnetic flux '$\phi' per turn in a coil of 'n' turns. Self inductance of the coil is 'L$'. The relation between them is

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