Question 271: Electromagnetic Induction

Question

A long solenoid has 1500 turns. When a current of $$3.5 \mathrm{~A}$$ flows through it, the magnetic flux linked with each turn of solenoid is $$2.8 	imes 10^{-3}$$ weber. The self-inductance of solenoid is

Accepted Answer

Flux linked with each turn of the solenoid is, $$\phi=2.8 	imes 10^{-3} \mathrm{~Wb}$$
$$	herefore \quad$$ Total magnetic flux of the solenoid is,
$$\begin{aligned}
& \phi_{	ext {net }}=\mathrm{N} \phi \
& \phi_{	ext {net }}=1500 	imes 2.8 	imes 10^{-3}=4.2 \mathrm{~Wb}
\end{aligned}$$
Flux can also be given by, $$\phi=\mathrm{LI}$$
$$	herefore \quad$$ The self-inductance of the solenoid is,
$$\begin{aligned}
& L=\frac{\phi}{I}=\frac{4.2}{3.5} \
& L=1.2 \mathrm{~H}
\end{aligned}$$

Answer

1.2 H

Answer

2.4 H

Answer

3.6 H

Answer

6 H

Electromagnetic Induction

A long solenoid has 1500 turns. When a current of $3.5 \mathrm{~A} flows through it, the magnetic flux linked with each turn of solenoid is 2.8 \times 10^{-3}$ weber. The self-inductance of solenoid is

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