Question 6: Electromagnetic Induction

Question

Given that in a fluorescent lamp's choke, a reverse voltage of 120 V is generated as the choke's current changes steadily from 0.50 A to 0.20 A in a time frame of 0.030 ms. Calculate the self inductance of the choke in millihenrys (mH).

Accepted Answer

Given, reverse voltage, E = 120 V
Change in current, $$\Delta$$I = 0.50 $$-$$ 0.20 = 0.30 A
Time, $$\Delta$$t = 0.030 ms = 0.030 $$	imes$$ 10
$$-$$3
s
In an inductor (choke),
Emf induced, $${E_{induced}} = L{{dl} \over {dt}}$$
$$	herefore$$ Self inductance of choke, $$L = {{E 	imes \Delta t} \over {\Delta I}}$$
$$ = {{120 	imes 0.030 	imes {{10}^{ - 3}}} \over {0.30}}$$
$$ = 12 	imes {10^{ - 3}}$$ H

Answer

12 H

Answer

12 $$	imes$$ 10$$-$$3 mH

Answer

12 $$	imes$$ 10$$-$$3 H

Answer

0

Electromagnetic Induction

Given that in a fluorescent lamp's choke, a reverse voltage of 120 V is generated as the choke's current changes steadily from 0.50 A to 0.20 A in a time frame of 0.030 ms. Calculate the self inductance of the choke in millihenrys (mH).

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