Question 265: Electromagnetic Induction

Question

A rod of length ' $l$ ' is rotated with angular velocity ' $\omega$ ' about its one end, perpendicular to a magnetic field of induction ' $B$ '. The e.m.f. induced in the rod is

Accepted Answer

A conducting rod of length ' $l$ ' whose one end is fixed, is rotated about the axis passing through its fixed end and perpendicular to its length with constant angular velocity $\omega$.
E.M.F induced, $\mathrm{e}=\mathrm{B} \pi l^2 \mathrm{n}=\frac{\mathrm{B} \pi l^2}{\mathrm{~T}}$
$	herefore \quad \mathrm{e}=\frac{1}{2} \mathrm{~B} l^2 \omega=0.5 \mathrm{~B} l^2 \omega \quad \ldots\left(\because \omega=\frac{2 \pi}{\mathrm{~T}}ight)$

Answer

$\mathrm{B} l^2 \omega$

Answer

$0.5 \mathrm{~B} l^2 \omega$

Answer

$B / \omega$

Answer

$0.5 \mathrm{~B} / \omega$

Electromagnetic Induction

A rod of length ' l ' is rotated with angular velocity ' \omega ' about its one end, perpendicular to a magnetic field of induction ' B '. The e.m.f. induced in the rod is

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