Question 243: Electromagnetic Induction

Question

The number of turns in the primary of a transformer are 1000 and in secondary 3000. If 80 V a.c. is applied to the primary, the potential difference per turn of the secondary coil is

Accepted Answer

In a transformer, the relationship between the number of turns and the voltage can be given by the transformer equation:
$$ \frac{V_p}{V_s} = \frac{N_p}{N_s} $$
where:
$ V_p $ is the primary voltage,
$ V_s $ is the secondary voltage,
$ N_p $ is the number of turns in the primary coil,
$ N_s $ is the number of turns in the secondary coil.
Given that $ N_p = 1000 $, $ N_s = 3000 $, and $ V_p = 80 \, 	ext{V} $, we need to find $ V_s $, the voltage across the secondary coil.
First, calculate $ V_s $:
$$ V_s = V_p \cdot \frac{N_s}{N_p} = 80 \cdot \frac{3000}{1000} $$
$$ V_s = 80 \cdot 3 $$
$$ V_s = 240 \, 	ext{V} $$
Next, find the potential difference per turn of the secondary coil. Since there are 3000 turns in the secondary coil:
$$ 	ext{Potential difference per turn} = \frac{V_s}{N_s} = \frac{240}{3000} $$
$$ = 0.08 \, 	ext{V} $$
So, the potential difference per turn of the secondary coil is
0.08 V
.
Option C: 0.08 V
.

Answer

0.02 V

Answer

0.04 V

Answer

0.08 V

Answer

0.16 V

Electromagnetic Induction

The number of turns in the primary of a transformer are 1000 and in secondary 3000. If 80 V a.c. is applied to the primary, the potential difference per turn of the secondary coil is

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