Question 236: Electromagnetic Induction

Question

The mutual inductance of two coils is 45 mH . The self-inductance of the coils are $\mathrm{L}_1=75 \mathrm{mH}$ and $\mathrm{L}_2=48 \mathrm{mH}$. The coefficient of coupling between the two coils is

Accepted Answer

The coefficient of coupling ($k$) between two coils can be calculated using the mutual inductance ($M$) and the self-inductances ($L_1$ and $L_2$) of the coils. The formula for the coefficient of coupling is:
$$ k = \frac{M}{\sqrt{L_1 \cdot L_2}} $$
Given:
$M = 45 \, 	ext{mH}$
$L_1 = 75 \, 	ext{mH}$
$L_2 = 48 \, 	ext{mH}$
Substitute the given values into the formula:
$$ k = \frac{45 \, 	ext{mH}}{\sqrt{75 \, 	ext{mH} \cdot 48 \, 	ext{mH}}} $$
Calculate the product inside the square root:
$$ 75 \cdot 48 = 3600  $$
So:
$$ \sqrt{3600} = 60 $$
Now, plug the values back into the formula:
$$ k = \frac{45}{60} = 0.75 $$
Thus, the coefficient of coupling is 0.75. The correct option is C: 0.75.

Answer

0.3

Answer

0.4

Answer

0.75

Answer

1.0

Electromagnetic Induction

The mutual inductance of two coils is 45 mH . The self-inductance of the coils are \mathrm{L}_1=75 \mathrm{mH} and \mathrm{L}_2=48 \mathrm{mH}. The coefficient of coupling between the two coils is

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