Question 211: Electromagnetic Induction

Question

When a current in the conducting coil is changed from 5 A in one direction to 5 A in opposite direction in 0.5 second, an average induced e.m.f in the coil is 2 V . The selfinductance of the coil is

Accepted Answer

We are given:
Initial current $I_1 = 5 \, 	ext{A}$
Final current $I_2 = -5 \, 	ext{A}$
Change in current:
$\Delta I = I_2 - I_1 = -5 - 5 = -10 \, 	ext{A}$
Time interval: $\Delta t = 0.5 \, 	ext{s}$
Average induced emf: $E = 2 \, 	ext{V}$.
Formula:
$ E = L \frac{\Delta I}{\Delta t} $
Taking magnitude values:
$ L = \frac{E \cdot \Delta t}{|\Delta I|} $
Substitution:
$ L = \frac{2 	imes 0.5}{10} = \frac{1}{10} = 0.1 \, 	ext{H} $
$ L = 100 \, 	ext{mH} $
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Answer: Option D (100 mH)

Answer

25 mH

Answer

50 mH

Answer

75 mH

Answer

100 mH

Electromagnetic Induction

When a current in the conducting coil is changed from 5 A in one direction to 5 A in opposite direction in 0.5 second, an average induced e.m.f in the coil is 2 V . The selfinductance of the coil is

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