Question 198: Electromagnetic Induction

Question

The plot of magnetic flux ' $\phi$ ' linked with the coil versus current ' I ' is as shown in figure for two inductors $\mathrm{L}_1$ and $\mathrm{L}_2$. The self inductance of

Accepted Answer

Flux, $\phi=\mathrm{LI}$
Comparing the above equation with $\mathrm{y}=\mathrm{mx}$, $\mathrm{L}=\phi / \mathrm{I}$, which is the slope of the graph. Since slope of $L_1$ is greater, the value of selfinductance for $L_1$ is greater than that of $L_2$.

Answer

$\quad \mathrm{L}_1$ is equal to that of $\mathrm{L}_2$.

Answer

$\quad \mathrm{L}_1$ is less than that of $\mathrm{L}_2$.

Answer

$\quad \mathrm{L}_1$ is greater than that of $\mathrm{L}_2$.

Answer

$\quad \mathrm{L}_1$ is half that of $\mathrm{L}_2$.

Electromagnetic Induction

The plot of magnetic flux ' \phi ' linked with the coil versus current ' I ' is as shown in figure for two inductors \mathrm{L}_1 and \mathrm{L}_2. The self inductance of

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